Finding Ship Tonnage with Blocks

[Patron Zero]

I'm having a difficulty with a ship design under development that's been quite a challenge and am considering the following to resolve such.

According to the text in CT Sup7:Traders & Gunboats (page 5), one (1) ton of displacement is measured as four (4) 1.5M cubes equaling 14 (actually 13.5) cubic meters. So a 1.5 'cube' is 1/4 of a ton for simplicity sake.

That said, the ship I'm sorting out has an annular wing of approximately 35Tons, the rings diameter is an estimated 21M and 1.5M wide. Finding the height is where I'm stuck at the moment.

So I'm looking at using the WIP deckplan as a 'template' to place scaled 1.5M 'blocks' to compute the raw volume of the annular ring structure itself.

Yes, I'm admittedly math-challenged in some areas but think the method of using 'blocks' might help bring me to a rough solution.

 

[atpollard]

Just to make sure that I am understanding the object correctly ...

You have a 'donut' that is 35 dTons (35 x 14 = 490 cubic meters).
The diameter of the donut hole is 21 meters and the donut ring is 1.5 meters wide ... so the outside diameter of the donut is 24 meters (21 + 1.5 + 1.5).
And the question is how much do you need to stack the donut vertically to create 35 dTons.

Have I understood correctly?

If so, then let's treat it like a cylinder and find the height from the area:

Outer Circle = 24m diameter = 12 m radius ... area=12 x 12 x 3.14 = 452 sq.m.
Inner Circle = 21m diameter = 10.5 m radius ... area=10.5 x 10.5 x 3.14 = 346 sq.m.

area of ring = 452 - 346 = 106 sq meters

since the total volume = 490 cu.m. (35 dT x 14) ...
average height will be 490 / 106 = 4.6 meters

so one solution is a ring 1.5 meters wide x 4.6 meters tall ...
... or any other shape that will be 6.9 square meters (1.5 x 4.6) in sectional area and your given 1.5 meters wide ... draw it in section to get the sectional area shaped how you want it.

 

[Meteoric Assault]

Coincidence

Just to make sure that I am understanding the object correctly ...

You have a 'donut' that is 35 dTons (35 x 14 = 490 cubic meters).
The diameter of the donut hole is 21 meters and the donut ring is 1.5 meters wide ... so the outside diameter of the donut is 24 meters (21 + 1.5 + 1.5).
And the question is how much do you need to stack the donut vertically to create 35 dTons.

Have I understood correctly?

If so, then let's treat it like a cylinder and find the height from the area:

Outer Circle = 24m diameter = 12 m radius ... area=12 x 12 x 3.14 = 452 sq.m.
Inner Circle = 21m diameter = 10.5 m radius ... area=10.5 x 10.5 x 3.14 = 346 sq.m.

area of ring = 452 - 346 = 106 sq meters

since the total volume = 490 cu.m. (35 dT x 14) ...
average height will be 490 / 106 = 4.6 meters

so one solution is a ring 1.5 meters wide x 4.6 meters tall ...
... or any other shape that will be 6.9 square meters (1.5 x 4.6) in sectional area and your given 1.5 meters wide ... draw it in section to get the sectional area shaped how you want it.

I was looking at Adv 2. and saw where on page 11, "Space flight tonnage (computed at 1 ton equals 14 cubic meters)". What has been shared above gives greater clarity and scale.

 

[salochin999]

I'm not very metric so I find it a lot easier to think in 10' cubes (or 4 x 5' cubes) but yeah visualizing it as blocks seems like it might help.

wing of approximately 35Tons, the rings diameter is an estimated 21M and 1.5M wide

35 dtons means
- 35 x 10' cube blocks (edit: 17.5)
or
- 140 x 5' cube blocks

using the second option if the rings diameter is 21m (14 blocks) then the circumference is diameter x pi ~ 43 blocks

so with a width of 1 block and a circumference of c.44 blocks

then the height would be (140 total blocks / 44) ~ 3 and a bit blocks high (c. 16 feet ish)

(trust my arithmetric at own risk)

(it'll be a bit different from others due to using squares)

 

[atpollard]

I'm not very metric so I find it a lot easier to think in 10' cubes (or 4 x 5' cubes) but yeah visualizing it as blocks seems like it might help.



35 dtons means
- 35 x 10' cube blocks
or
- 140 x 5' cube blocks

using the second option if the rings diameter is 21m (14 blocks) then the circumference is diameter x pi ~ 43 blocks

so with a width of 1 block and a circumference of c.44 blocks

then the height would be (140 total blocks / 44) ~ 3 and a bit blocks high (c. 16 feet ish)

(trust my arithmetric at own risk)

(it'll be a bit different from others due to using squares)

... shhh. Don't tell anyone, but I create deckplans on a 5' module and just call it 1.5 m grids.

But a 10' cube is 2 dTons, so 35 dTons is 17.5 x 10' cubes or 140 x 5' cubes.
(it might just be a typo in your post).

 

[salochin999]

... shhh. Don't tell anyone, but I create deckplans on a 5' module and just call it 1.5 m grids.

But a 10' cube is 2 dTons, so 35 dTons is 17.5 x 10' cubes or 140 x 5' cubes.
(it might just be a typo in your post).

no, definitely a mistake, ty