Sttuterwarp drive table (pages 199-200):
The tonnage and Price for Old Commercial drives are lower tan otheres, while the New Military ones are the ones with higer tonnage and price. While in the case of price this is logical, I'm afraid the tonages should be reversed, NM being the one that needs lower tonage and OC the one needing higer.
Even with the modifiers to stutterwarp (x 1.07 for NC/OM and x 1.15 for NM), the more efficient one is the OC.
Even so, when you feature the PP on the equation, things change a little (to say the least)
To give you an example, if we have a 1000 dton ship and we want a warp performance of 2:
Warp drive | WP(modified) | tonnage | cost(MLv) | PP tonnage | PP cost | Total Tonnage | Total cost |
P(OC) | 2.18 | 1.93 | 5.79 | 35.71 | 3.13 | 37.64 | 8.92 |
N(NC/OM) | 2.16 | 2.03 | 6.09 | 28.57 | 2.5 | 30.6 | 8.59 |
M(NM) | 2.12 | 2.14 | 6.41 | 21.43 | 1.88 | 23.59 | 8.29 |
But if the hull was only 400 dton, to reach WP 2 you'd need L rated WP even if using NM tech (WP 1.73 x 1.15 = 1.99).
For this table, PP is assumed to be the same letter than WD, and in all cases OC tech MHD. So, if you were using NC/OM or NM MHD tech, the tonnage saved will be greater, while the cost will raise a Little. Costs/tonnage for raditors and fuel are not featured in the table.
So, it seems it might be efficient on large hulls, or for higher WP, where it allows you to have smaller PP and reach the same WP, while the WP diference in smaller hulls with low WP makes them inefficient. It seems it must be calculated on a case per case basis to see if it allows you to reduce your PP size.