Email me at don.mckinney@gmail.com. I have an idea....
:devil:
I'll do that when I get home from work this afternoon.
Email me at don.mckinney@gmail.com. I have an idea....
:devil:
GL = Grenade Launcher?
Fusion Gun Turrets ----------UCP Factor---------
TL Type Power Wt Price 1 2 3 4 5 6 7 8 9 A
12 Fusion Turret 500 5 2000000 - - - 1 4 10 16 20 - -
14 Fusion Turret 500 5 2000000 - - - - 1 4 10 16 20 -
17 Fusion Turret 500 5 2000000 - - - - - 1 4 10 16 20
Fusion Gun Turrets ----------UCP Factor---------
TL Type Power Wt Price 1 2 3 4 5 6 7 8 9 A
12 Fusion Turret 500 5 2000000 - - - 1 4 10 16 20 - -
14 Fusion Turret 500 [b]_4_[/b] 2000000 - - - - 1 4 10 16 20 -
17 Fusion Turret 500 [b]_3_[/b] 2000000 - - - - - 1 4 10 16 20
I am questioning the 1988 Errata for RM page 74 Fusion Gun table.
Why was the weight changed to 5 for all TL? The original TL 12: 5, TL 14: 4 and TL 17: 3 is consistent with all other turret weight figures.
Should it be:
Thoughts?Code:Fusion Gun Turrets ----------UCP Factor--------- TL Type Power Wt Price 1 2 3 4 5 6 7 8 9 A 12 Fusion Turret 500 5 2000000 - - - 1 4 10 16 20 - - 14 Fusion Turret 500 [B]_4_[/B] 2000000 - - - - 1 4 10 16 20 - 17 Fusion Turret 500 [B]_3_[/B] 2000000 - - - - - 1 4 10 16 20
-Swiftbrook
This is some of the oldest errata... but that certainly doesn't make it perfect. But I would want some more input on this.
MT RM p.82 said:Cm=(H+A)/C/400 (drop fractions)
Original '88 Errata said:Maintenance Crew formula (Cm): A=Hull displacement divided by 100, H=Hull CP.
MT Errata said:On the Maintenance Crew formula (Cm), Cm = (A ÷ C) ÷ 400 (drop fractions), where A=Hull displacement divided by 100.
Errata the Errata #2
On Starship design maintenance crew formula:
Unfortunately on a million displacement ton hull the Consolidated Errata formula work out like this:
1,000,000/100 = 10,000
10,000/5 = 2,000 (5 is the smallest Computer CP multiplier)
2,000/400 = 5
That's a maintenance crew of 5 for a million ton ship run by a TL 5 computer. Much too low.
If you add back in the CPs for the hull, roughly 5,000,000 you get
1,000,000/100 + 5,000,000 = 6,000,000
6,000,000/65 = 92,000 (for a type 7 computer)
92,000/4 = 23,000
Which is too high.
Any ideas?
Edit: An idea. On the Maintenance Crew formula (Cm), Cm = (A ÷ C) (drop fractions), where A=Hull displacement divided by 100.
I dropped the ÷ 400. A 100,000t hull with a type 6 computer (mult of 45) will have about 22 maintenance crew.
-Swiftbrook
I'm afraid your numbers are not fully correct here:
1,000,000/100 + 5,000,000 = 5,010,000
5,010,,000/65 = 77,077(for a type 7 computer)
77,077/400 = 192
I guess the formula I like the most is the original from MT, at least in this case.
Item Volume Weight Cost
===================================================
Sickbay/Medical Bay 108 8 5 MCr
Laboratory 108 8 5 MCr
Autodoc 13.5 1 1 MCr
Engineering Shop 81 6 1 MCr
Vehicle Shop 135 10 2 MCr