One of the frustrations of playing a game which only calls for D6 is that when a situation could be most equitably resolved by an even chance dice roll for a number of results greater than 6 you may not have dice available to do so. For instance, this is the reason for the 1-9 and 0-9 even distribution charts on page 31.... Which you won't need to bother turning too once you learn this method.
Here is an example of the process (before I go into the details of how it works):
Lets say you want to randomly determine a career for an NPC you are fleshing out because they just went from being a nobody in your game to being important, and all you know so far is their name and that they will be traveling with the PC's for a couple sessions at least. So you decide you want to roll an even distribution across the careers list on page 182 rather than Flux which results in Spacer, Merchant, and Soldier dominating the results. This is 13 possible results... So you divide them into 3 groups, 1-6,7-12, and 13, and assign each group to an even distribution on D6. So 1-2 = 1-6, 3-4 = 7-12, and 5-6 = 13. You then roll a D6 for the distribution and then another D6 for the results. If your result is more than "13", then you start over from the very beginning. So here are the two dice rolls in order and what the result would be: 1,4=4. 2,2=2. 3,1=7. 4,5=11. 5,1=13. 6,2 (or 3,4,5,or 6) = start over.
That is the process for even distribution of any 1 to X roll from 1-7 to 1-36 (or 0-6 to 0-35).... Divide into groups of 6, assign a number (or 2 or 3, depending on whether you have 4+ groups, 3 groups, or 2 groups, respectively) to each group of 6, and roll until you get a valid result. If the result is invalid start completely from the beginning, do not re-roll partway through the process or it is no longer even distribution.
Here are couple examples of distributions to use:
0-9 means 1-3 = 0-5, 4-6 = 6-9, and 10-11 = full restart
1-27 means 1 = 1-6, 2 = 7-12, 3 = 13-18, 4 = 19-24, 5 = 25-27 and 28-30 = full restart.
This can also be used for larger than 1-36 by adding more layers to the process. For instance:
1-83 means 1-2 = 1-36, 3-4 = 37-72, 5-6 = 73-83, then repeat the process above for each of these subgroups (make sure to use the full 1-36 process for the 73-83 section and restart if the results isn't 1-11).
Another option for 1-83 would be to use the 0-9 process mentioned above to make two 0-9 rolls that simulate the 1-100 roll you would probably use if you had D10's available. Just remember to restart entirely if the result is greater than 83.
This can also be used for other dice rolls like 2d8. Just roll two 1-8's separately and add them together. The good news here is that you don't have to restart both rolls if one of them fails. Just do the first until it works, then do the second until it works.
This seems rather complex, and I admit it can be pretty rough when doing very large numbers, but in my experience it is very rare that you need even distribution amongst anything larger than 1-36, and it won't take long to get used to doing the 1-36 thing entirely off the top of your head.
Here is an example of the process (before I go into the details of how it works):
Lets say you want to randomly determine a career for an NPC you are fleshing out because they just went from being a nobody in your game to being important, and all you know so far is their name and that they will be traveling with the PC's for a couple sessions at least. So you decide you want to roll an even distribution across the careers list on page 182 rather than Flux which results in Spacer, Merchant, and Soldier dominating the results. This is 13 possible results... So you divide them into 3 groups, 1-6,7-12, and 13, and assign each group to an even distribution on D6. So 1-2 = 1-6, 3-4 = 7-12, and 5-6 = 13. You then roll a D6 for the distribution and then another D6 for the results. If your result is more than "13", then you start over from the very beginning. So here are the two dice rolls in order and what the result would be: 1,4=4. 2,2=2. 3,1=7. 4,5=11. 5,1=13. 6,2 (or 3,4,5,or 6) = start over.
That is the process for even distribution of any 1 to X roll from 1-7 to 1-36 (or 0-6 to 0-35).... Divide into groups of 6, assign a number (or 2 or 3, depending on whether you have 4+ groups, 3 groups, or 2 groups, respectively) to each group of 6, and roll until you get a valid result. If the result is invalid start completely from the beginning, do not re-roll partway through the process or it is no longer even distribution.
Here are couple examples of distributions to use:
0-9 means 1-3 = 0-5, 4-6 = 6-9, and 10-11 = full restart
1-27 means 1 = 1-6, 2 = 7-12, 3 = 13-18, 4 = 19-24, 5 = 25-27 and 28-30 = full restart.
This can also be used for larger than 1-36 by adding more layers to the process. For instance:
1-83 means 1-2 = 1-36, 3-4 = 37-72, 5-6 = 73-83, then repeat the process above for each of these subgroups (make sure to use the full 1-36 process for the 73-83 section and restart if the results isn't 1-11).
Another option for 1-83 would be to use the 0-9 process mentioned above to make two 0-9 rolls that simulate the 1-100 roll you would probably use if you had D10's available. Just remember to restart entirely if the result is greater than 83.
This can also be used for other dice rolls like 2d8. Just roll two 1-8's separately and add them together. The good news here is that you don't have to restart both rolls if one of them fails. Just do the first until it works, then do the second until it works.
This seems rather complex, and I admit it can be pretty rough when doing very large numbers, but in my experience it is very rare that you need even distribution amongst anything larger than 1-36, and it won't take long to get used to doing the 1-36 thing entirely off the top of your head.
