Plankowner's equations are close enough for government work. There are also some good tables for travel times in the magazine-sized CT books (one book was entirely devoted to tables). I'm not sure if that stuff was in the LBBs....
I'll just point out that if you don't perform turnaround, you'll have a velocity at destination of (173,000 seconds x 9.81 m/s^2 =) 1.7 million m/s.
1.7E6 m/s is 6.1 million km/h, or 1/2% of the speed of light. You won't be able to stop until you've (a) arrested all of your velocity, which will take another 2 days, and (b) returned to the destination using turnaround, which will take another 2.8 days.
Plankowner's little equation is very nice because it's in AU (150,000,000 km or thereabouts), which gives you a good idea of how far a ship with fusion drives can go. The space shuttle has about a 3G takeoff, but can't sustain that thrust for longer than a few paltry minutes.
(Altitude at main engine cutoff (MECO) is 113 km, and assuming atmospheric resistance quadruples the acceleration time, that's like 6 minutes. I think that in real life, it's about 8-1/2 minutes to MECO because they cut the main engine thrust back to 25% while they're in deep atmosphere so atmospheric heating doesn't burn up the shuttle...)